Example 4 Graph f(x) = x^2 -2x - 8
Steps to Graph ax^2 + bx + c
- Find the vertex and the axis of symmetry. Sketch these in.
- Find the x-intercept by plugging in 0 for y.
- Find the y-intercept by plugging in 0 for x.
- Reflect your points across the axis of symmetry and connect your dots with a smooth U-shaped (not V-shaped) curve.
Graph f(x) = x^2 -2x - 8
the axis of symmetry is -9

for nownow, I'm just gonna type my work and figure out what to do next
fubdfind the line of symetrymsymmetry -(b/2a)=x
- a = 1, b = -2, c = -8
use this to find
the vertex
x = (b/2a)
x = -(-2) / 2(1) = 1
since we know that the along the x axis at 1 will be the vertex we replace x with 1 in the original formula
x=1
y = x^2 -2x - 8
y = 1^2 + -2 * 1 -
8=8 = 1- 2 - 8 = -9
y =
y-9
the vertex is
x,(1, -
99)
findsince the vertex is -1,-9 we know that x=1 is the axis of
symetrysymmetry
finding the
axis of symmetryy-intercept is
the easiest to start with because we just replace x with 0
x = 0 | y = x^2 -
92x - 8
y = 0 - 8 = -8
y-intercept = (0,-8)
so so To find the x-intercepts, you can set y equal to zero and solve for x:
x^
y = 0 | x = (-b ± sqrt(b^2 - 2x4ac)) / 2a
x = (-(-2) ± sqrt((-2)^2 - 84(1)(-8))) / 2(1)
x = 0
(x2 -± 4)(xsqrt(4 + 2)32)) / 2
x = 0
(2 ± sqrt(36)) / 2
x = (2 ± 6) / 2
x = 8 / 2 or x = -4/ 2
x = 4 or x = -2
sooooo (-2,0) & (4,0)
so since we know 3 y axis points on the graph and the axis of symmetry we can get another point without doing much work
symmetry line = x = 1,
calc'd x-intercept 0,-8
the symmetry line is 1 and the known point is 0 since 1-0 = 1 we can add that to the x coordinate of y and keep the same y coordinate to get the mirrored point making another point on the graph (2,-8)
since we need one more point for the graph we can choose say x=3, | x^2 -2x - 8
y = 3^2 -3*2 - 8 = -5
soooo the new point is (3,-5) if we mirror that along 1,-9 we get (-1, -5 ) because 3 is 2 more than 1, and 2 less than 1 is -1. we also keep the same y coordinate
so all points are:
(1, -9)
(0,-8)
(2, -8)
(3,-5)
(-1,-5)